Games: Perplexity

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The Independent Online
For amusement only: Can you arrange the numbers 1 to 14 in a circle so that the sum of any two adjacent numbers equals the sum of the two numbers opposite them? In other words, if the order round the circle is a, b, c, d, e, f, g, h, i, j, k, l, m, n, then a+b=h+i; and b+c=i+j; and c+d=j+k, all the way round to n+a=g+h.

No prizes for this one. The answer will appear next week, together with the name of the winner of last week's Perplexity competition.

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